-16x^2+288x+6=0

Solution for -16x^2+288x+6=0 equation:

-16x^2+288x+6=0

a = -16; b = 288; c = +6;
Δ = b2-4ac
Δ = 2882-4·(-16)·6
Δ = 83328
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{83328}=\sqrt{64*1302}=\sqrt{64}*\sqrt{1302}=8\sqrt{1302}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(288)-8\sqrt{1302}}{2*-16}=\frac{-288-8\sqrt{1302}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(288)+8\sqrt{1302}}{2*-16}=\frac{-288+8\sqrt{1302}}{-32}
$